// // The Zig compiler provides "builtin" functions. You've already // gotten used to seeing an @import() at the top of every // Ziglings exercise. // // We've also seen @intCast() in "016_for2.zig", "058_quiz7.zig"; // and @enumToInt() in "036_enums2.zig". // // Builtins are special because they are intrinsic to the Zig // language itself (as opposed to being provided in the standard // library). They are also special because they can provide // functionality that is only possible with help from the // compiler, such as type introspection (the ability to examine // type properties from within a program). // // Zig contains over 100 builtin functions. We're certainly // not going to cover them all, but we can look at some // interesting ones. // // Before we begin, know that many builtin functions have // parameters marked as "comptime". It's probably fairly clear // what we mean when we say that these parameters need to be // "known at compile time." But rest assured we'll be doing the // "comptime" subject real justice soon. // const print = @import("std").debug.print; pub fn main() void { // The second builtin, alphabetically, is: // @addWithOverflow(a: anytype, b: anytype) struct { @TypeOf(a, b), u1 } // * 'a' and 'b' are numbers of anytype. // * The return value is a tuple with the result and a possible overflow bit. // // Let's try it with a tiny 4-bit integer size to make it clear: const a: u4 = 0b1101; const b: u4 = 0b0101; const my_result = @addWithOverflow(a, b); // Check out our fancy formatting! b:0>4 means, "print // as a binary number, zero-pad right-aligned four digits." // The print() below will produce: "1101 + 0101 = 0010 (true)". print("{b:0>4} + {b:0>4} = {b:0>4} ({s})", .{ a, b, my_result[0], if (my_result[1] == 1) "true" else "false" }); // Let's make sense of this answer. The value of 'b' in decimal is 5. // Let's add 5 to 'a' but go one by one and see where it overflows: // // a | b | result | overflowed? // ---------------------------------- // 1101 + 0001 = 1110 | false // 1110 + 0001 = 1111 | false // 1111 + 0001 = 0000 | true (the real answer is 10000) // 0000 + 0001 = 0001 | false // 0001 + 0001 = 0010 | false // // In the last two lines the value of 'a' is corrupted because there was // an overflow in line 3, but the operations of lines 4 and 5 themselves // do not overflow. // There is a difference between // - a value, that overflowed at some point and is now corrupted // - a single operation that overflows and maybe causes subsequent errors // In practise we usually notice the overflowed value first and have to work // our way backwards to the operation that caused the overflow. // // If there was no overflow at all while adding 5 to a, what value would // 'my_result' hold? Write the answer in into 'expected_result'. const expected_result: u8 = ???; print(". Without overflow: {b:0>8}. ", .{expected_result}); print("Furthermore, ", .{}); // Here's a fun one: // // @bitReverse(integer: anytype) T // * 'integer' is the value to reverse. // * The return value will be the same type with the // value's bits reversed! // // Now it's your turn. See if you can fix this attempt to use // this builtin to reverse the bits of a u8 integer. const input: u8 = 0b11110000; const tupni: u8 = @bitReverse(input, tupni); print("{b:0>8} backwards is {b:0>8}.\n", .{ input, tupni }); }