mirror of
https://codeberg.org/andyscott/ziglings.git
synced 2024-11-08 11:20:46 -05:00
73 lines
2.1 KiB
Zig
73 lines
2.1 KiB
Zig
//
|
|
// The Zig language is in rapid development and continuously
|
|
// improves the language constructs. Ziglings evolves with it.
|
|
//
|
|
// Until version 0.11, Zig's 'for' loops did not directly
|
|
// replicate the functionality of the C-style: "for(a;b;c)"
|
|
// which are so well suited for iterating over a numeric
|
|
// sequence.
|
|
//
|
|
// Instead, 'while' loops with counters clumsily stood in their
|
|
// place:
|
|
//
|
|
// var i: usize = 0;
|
|
// while (i < 10) : (i += 1) {
|
|
// // Here variable 'i' will have each value 0 to 9.
|
|
// }
|
|
//
|
|
// But here we are in the glorious future and Zig's 'for' loops
|
|
// can now take this form:
|
|
//
|
|
// for (0..10) |i| {
|
|
// // Here variable 'i' will have each value 0 to 9.
|
|
// }
|
|
//
|
|
// The key to understanding this example is to know that '0..9'
|
|
// uses the new range syntax:
|
|
//
|
|
// 0..10 is a range from 0 to 9
|
|
// 1..4 is a range from 1 to 3
|
|
//
|
|
// At the moment, ranges are only supported in 'for' loops.
|
|
//
|
|
// Perhaps you recall Exercise 13? We were printing a numeric
|
|
// sequence like so:
|
|
//
|
|
// var n: u32 = 1;
|
|
//
|
|
// // I want to print every number between 1 and 20 that is NOT
|
|
// // divisible by 3 or 5.
|
|
// while (n <= 20) : (n += 1) {
|
|
// // The '%' symbol is the "modulo" operator and it
|
|
// // returns the remainder after division.
|
|
// if (n % 3 == 0) continue;
|
|
// if (n % 5 == 0) continue;
|
|
// std.debug.print("{} ", .{n});
|
|
// }
|
|
//
|
|
// Let's try out the new form of 'for' to re-implement that
|
|
// exercise:
|
|
//
|
|
const std = @import("std");
|
|
|
|
pub fn main() void {
|
|
|
|
// I want to print every number between 1 and 20 that is NOT
|
|
// divisible by 3 or 5.
|
|
for (???) |n| {
|
|
|
|
// The '%' symbol is the "modulo" operator and it
|
|
// returns the remainder after division.
|
|
if (n % 3 == 0) continue;
|
|
if (n % 5 == 0) continue;
|
|
std.debug.print("{} ", .{n});
|
|
}
|
|
|
|
std.debug.print("\n", .{});
|
|
}
|
|
//
|
|
// That's a bit nicer, right?
|
|
//
|
|
// Of course, both 'while' and 'for' have different advantages.
|
|
// Exercises 11, 12, and 14 would NOT be simplified by switching
|
|
// a 'while' for a 'for'.
|