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83 lines
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2.8 KiB
Markdown
83 lines
No EOL
2.8 KiB
Markdown
# Last Will
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Welcome to Last Will on Exercism's C++ Track.
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If you need help running the tests or submitting your code, check out `HELP.md`.
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If you get stuck on the exercise, check out `HINTS.md`, but try and solve it without using those first :)
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## Introduction
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## Namespaces
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An important method for code organization are namespaces.
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Two functions might have a naming collision, which can be resolved by putting them in different namespaces.
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Namespaces can be nested, which might help to structure big code bases.
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Access to the namespaces is done via the scope-resolution operator `::`.
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The example below shows the use of two different `foo` functions.
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They are used together by prefixing their respective namespaces.
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```cpp
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namespace my_ns {
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int foo() {
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return 44;
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}
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namespace my_inner_ns {
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int baz() {
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return 90;
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}
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}
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}
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namespace my_other_ns {
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int foo() {
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return -2;
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}
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}
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int myresult{my_ns::foo() + my_other_ns::foo() * my_ns::my_inner_ns::baz()};
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```
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## Instructions
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You work for a prestigious law firm that is specialized in handling unique testament requests.
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In this exercise, you are going to open a mysterious vault.
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You are the executor of the estate and will assemble the long-kept secret codes of three families to get an account number and the matching code.
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To prevent any family from opening the vault alone, it can only be opened by combining their knowledge with a secret modifier that you know from the last will.
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You have three tasks, all related to helping the families to open the vault.
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## 1. Take your seat in front of the families and lay out your papers
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Define a namespace called `estate_executor`.
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The code from the next tasks should be defined in the body of the `estate_executor` namespace.
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```cpp
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namespace some_name {
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// The space between the curly brackets
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// is called body of the namespace.
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}
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```
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## 2. Find the secret account number
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This is your big moment.
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Only you have the secret modifier key to reveal the secret account number.
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Define the `assemble_account_number(int secret_modifier)` function that takes the secret modifier as an argument and returns the assembled account number as an `int`.
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To get the correct number, you have to sum up the `bank_number_part` from each of the three families.
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## 3. Last step: Enter the secret code
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The instructions in the testament ask you to add all the blue and then all the red fragments.
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The resulting code is obtained by multiplying both sums.
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Define the `assemble_code()` function that returns the resulting code by combining the fragments from the three families to a single `integer`.
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The function does not have any arguments and relies solely on the information in the relevant namespaces from the families.
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## Source
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### Created by
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- @vaeng |